0=20x-2x^2+3

Solution for 0=20x-2x^2+3 equation:

0=20x-2x^2+3

We move all terms to the left:

0-(20x-2x^2+3)=0

We add all the numbers together, and all the variables

-(20x-2x^2+3)=0

We get rid of parentheses

2x^2-20x-3=0

a = 2; b = -20; c = -3;
Δ = b2-4ac
Δ = -202-4·2·(-3)
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{106}}{2*2}=\frac{20-2\sqrt{106}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{106}}{2*2}=\frac{20+2\sqrt{106}}{4}
$